72=3u^2

Solution for 72=3u^2 equation:

72=3u^2

We move all terms to the left:

72-(3u^2)=0

a = -3; b = 0; c = +72;
Δ = b2-4ac
Δ = 02-4·(-3)·72
Δ = 864
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{864}=\sqrt{144*6}=\sqrt{144}*\sqrt{6}=12\sqrt{6}$
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12\sqrt{6}}{2*-3}=\frac{0-12\sqrt{6}}{-6}
=-\frac{12\sqrt{6}}{-6}
=-\frac{2\sqrt{6}}{-1}
$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12\sqrt{6}}{2*-3}=\frac{0+12\sqrt{6}}{-6}
=\frac{12\sqrt{6}}{-6}
=\frac{2\sqrt{6}}{-1}
$